Solving Inequalities

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Lesson Details

Grade Level
6-8
Duration (minutes)
2
Summary
A grade 6-8 math lesson teaching how to solve one-step inequalities, including the critical rule that dividing or multiplying by a negative number flips the inequality sign — with three worked examples and checks.

Solving inequalities with the rule that multiplying or dividing by a negative number flips the sign, shown in three examples: x+4 less than 10 solves to x less than 6, x−3 greater than 5 solves to x greater than 8, and −2x less than 8 solves to x greater than −4 after flipping the sign

Student Worksheet: Solving Inequalities

Teacher Note: Students can watch the video lesson above and answer the questions. Click the “Teacher Answer Key” dropdown below when you are ready to review the solutions!

Key Concepts:

• Same Operation: Adding, subtracting, multiplying, or dividing must be done to both sides.

• Sign Stays the Same: When adding, subtracting, or multiplying/dividing by a positive number.

• Flip the Sign: Only when multiplying or dividing both sides by a negative number.

Instructions: Read each question carefully and write your answer in the space provided.

  1. Question 1: Solve: x + 4 < 10
  2. Question 2: Solve: x − 3 > 5
  3. Question 3: Solve: −2x < 8
  4. Question 4: When do you need to flip the inequality sign?
  5. Question 5: If you forgot to flip the sign in Question 3, would the check with x = 0 still work? Explain.
Click to reveal Teacher Answer Key

1. x < 6

2. x > 8

3. x > −4

4. Only when multiplying or dividing both sides by a negative number

5. No, the check would fail, because 0 is not less than −4

Disclaimer: This worksheet was generated with AI assistance based on original video content. It is intended for educational reference only. Teachers are encouraged to review and adjust questions to fit their curriculum standards before classroom use.

🎯 Extension Activity: Give students a new inequality, like −3x > 12, and have them solve it, remembering to flip the sign, then check their answer by substituting a value back in.

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